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9x^2-119x+288=0
a = 9; b = -119; c = +288;
Δ = b2-4ac
Δ = -1192-4·9·288
Δ = 3793
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-119)-\sqrt{3793}}{2*9}=\frac{119-\sqrt{3793}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-119)+\sqrt{3793}}{2*9}=\frac{119+\sqrt{3793}}{18} $
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